C++ program to calculate diameter, area and perimeter of a circle has been given below. Suppose, the radius of a circle is r unit, the area and perimeter of that circle would be (pi * r^2) unit^2 and (2 * pi * r) unit, respectively while the diameter would be 2 * r. The approximate value of pi is 3.141592.
For example, if the radius of a circle is 5 cm, then area of the circle would be (pi * 5^2) = 78.54 cm^2 while perimeter and diamerter would be (2 * pi * r) = 31.42 cm and (2 * r) = 10 cm respectively.
The algorithm, pseudocode, and time-complexity of the program have also been covered below.
1. Algorithm to calculate diameter, area and perimeter of a circle
1. Take the radius r of a circle as input.
2. Compute d = 2 * r
3. Compute a = pi * r^2
4. Compute p = 2 * pi * r
5. Declare d as the diameter, a as the area and p as the perimeter of that circle.
2. Pseudocode to calculate diameter, area and perimeter of a circle
Input : Radius r of a circle
Output : Diameter D, Area A, Perimeter P of the circle
1. Procedure diameterAreaPerimeter(r):
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6. End Procedure
3. Time complexity to calculate diameter, area and perimeter of a circle
Time Complexity: O(1)
4. C++ Program & Output to calculate diameter, area and perimeter of a circle
/*********************************** alphabetacoder.com C++ program to calculate diameter, area and perimeter of a circle ***********************************/ #include <iostream> #define pi 3.141592 using namespace std; int main() { // declare variables float r, d, a, p; // take input cout << "Enter the radius of a circle: "; cin >> r; // calculare diameter d = 2 * r; // calculate area a = pi * r * r; // calculate perimeter p = 2 * pi * r; // display result cout << "Diameter: " << d << endl; cout << "Area: " << a << endl; cout << "Perimeter: " << p << endl; return 0; }
Output
Enter the radius of a circle: 6
Diameter: 12
Area: 113.097
Perimeter: 37.6991