C++ Program to Find the Largest Among Three Numbers

C++ program to find the largest among three numbers can be computed by comparing them with each other. A number x is said to be the largest among three numbers when its value is greater than other two numbers say y and z. For example, 20 is the largest among three numbers 10, 15, 20.

Page content(s):

1. Algorithm

2. Pseudocode

3. Time Complexity

4. Program & Output

Additional content(s):

1. Flowchart

1. Algorithm to find the largest among three numbers

// $x$, $y$, $z$ are three input numbers//

1. Check if $x$ is greater or equal to $y$

2. If step [1] is true, then check if $x$ is greater or equal to $z$

3. If step [2] is true, then print $x$ is the largest

4. If step [2] is false, then print $z$ is the largest

5. If step [1] is false, then check if $y$ is greater or equal to $z$

6. If step [5] is true, then print $y$ is the largest

7. If step [5] is false then print $z$ is the largest

2. Pseudocode to find the largest among three numbers

Input: Three numbers $x$, $y$, $z$

Output: Largest among $x$, $y$, $z$

1. Procedure findLargest($x$, $y$, $z$):

2. If $x \geq y$:

3. If $x \geq z$:

4. Return $x$

5. Else:

6. Return $z$

7. Else:

8. If $y \geq z$:

9. Return $y$

10. Else:

11. Return $z$

12. End Procedure

3. Time Complexity to find the largest among three numbers

Time Complexity: O(1)

4. C++ Program to find the largest among three numbers

Code has been copied

/************************************************
               alphabetacoder.com
 C++ program to find largest among three numbers
*************************************************/

#include <iostream>

using namespace std;

int main() {
    // declare variables
    int x, y, z;

    //take input of three numbers
    cout << "Enter the three numbers = ";
    cin >> x;
    cin >> y;
    cin >> z;

    // find the largest number
    if (x >= y) {
        if (x >= z)
            cout << x << " is the largest number.";
        else
            cout << z << " is the largest number.";
    } else {
        if (y >= z)
            cout << y << " is the largest number.";
        else
            cout << z << " is the largest number.";
    }

    return 0;
}

Output

Case 1:

Enter the three numbers = -13 -18 -23

-13 is the largest number.

Case 2:

Enter the three numbers = 10 20 30

30 is the largest number.