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C++ Program to Check if a number is even or odd

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Logic to check if a number is odd or even

C++ programs to check if a number is even or odd have been shown here. An integer number $n$ is said to be even if it is divisible by $2$ i.e. $(n\mod 2 = 0)$ and it is called odd if it is not divisible by 2 i.e. it does not result in 0 as the remainder when divided by $2$. So a number in the form of $2n$, where $n$ is an integer, is called even and a number in the form of $2n+1$ or $2n-1$ is called odd. For example $... -4, -2, 0, 2, 4$ ... etc. are even numbers and $... -3, -1, 1, 3, 5$ ... etc. are odd numbers.

  Another approach is to apply bitwise AND operator (&) to check if $n$ is even or odd. We need to perform bitwise AND operation between $n$ and $1$. If $n$ AND $1 = 0$, then $n$ is even and if $n$ AND $1 = 1$, then $n$ is odd.






1. Algorithm to check if a number is even or odd


// $n$ is an integer number as input//


1. Check if $n \mod 2 = 0$, then Return Even else

2. Return Odd





2. Pseudocode to check if a number is even or odd


Input: An integer number $n$

Output: If $n$ is even or odd

1. Procedure evenOrOdd($n$):

2. If $n\mod2==0$:

3. Return even

4. Else:

5. Return odd

6. End Procedure





3. Time complexity to check if a number is even or odd


Time Complexity: O(1)





4. C++ Program to check if a number is even or odd

Code has been copied
/************************************************
              alphabetacoder.com
 C++ program to check if a number is even or odd
*************************************************/

#include <iostream>

using namespace std;

int main() {
    // declare variable
    int n;

    //take input
    cout << "Enter the number = ";
    cin >> n;

    //check if n is even or odd
    if (n % 2 == 0)
        cout << n << " is even";
    else
        cout << n << " is odd";

    return 0;
}

Output

Case 1:

Enter the number = -5

-5 is odd


Case 2:

Enter the number = 8

8 is even


Case 3:

Enter the number = 3

3 is odd




5. C++ Program to check if a number is even or odd using bitwise AND operation

Code has been copied
/***************************************
        alphabetacoder.com
 C++ program to check if a number is 
 even or odd using bitwise AND operation
****************************************/

#include <iostream>

using namespace std;

int main() {
    // declare variable
    int n;

    //take input
    cout << "Enter the number = ";
    cin >> n;

    //check if n is even or odd
    // by doing bitwise AND operation
    // with 1. If the result is 0 then
    // n is even. If the result is 1 
    // then n is odd.
    if (n & 1)
        cout << n << " is odd";
    else
        cout << n << " is even";

    return 0;
}

Output

Case 1:

Enter the number = 15

15 is odd


Case 2:

Enter the number = 22

22 is even


Case 3:

Enter the number = 13

13 is odd




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